0=23(x+y)(4y)(y^2)

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Solution for 0=23(x+y)(4y)(y^2) equation:


Simplifying
0 = 23(x + y)(4y)(y2)

Remove parenthesis around (4y)
0 = 23(x + y) * 4y(y2)

Reorder the terms for easier multiplication:
0 = 23 * 4y * y2(x + y)

Multiply 23 * 4
0 = 92y * y2(x + y)

Multiply y * y2
0 = 92y3(x + y)
0 = (x * 92y3 + y * 92y3)
0 = (92xy3 + 92y4)

Solving
0 = 92xy3 + 92y4

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-92xy3' to each side of the equation.
0 + -92xy3 = 92xy3 + -92xy3 + 92y4
Remove the zero:
-92xy3 = 92xy3 + -92xy3 + 92y4

Combine like terms: 92xy3 + -92xy3 = 0
-92xy3 = 0 + 92y4
-92xy3 = 92y4

Divide each side by '-92y3'.
x = -1y

Simplifying
x = -1y

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